iMaths Practise 2 Solution

Q1. Case 1
X = unit + 30
Y = unit - 30

Case 2
X = unit + 30 + 18
Y = unit - 30 - 18
unit+30+18 = 4(unit-30-18)
unit+48 = 4units-192
3 units = 240
1 unit = 80
At first, X = unit+30 = 80+30=110

At first,number of beads in Box X was 110.

Q2. In the end, all 3 containers became equal.
So, P=Q=E = 162 divided by 3 = 54
R(Original) = 54 divided by 3 = 18
Q(Before giving R and after receiving from P)= 54+18x2 = 90
Q(Original) = 90 divided by 3 = 30
P(Original) = 54+30x2 = 114

Number of buttons in container P at first = 114.

Q3. In the end,
X = 115
Y = 90
2/3 of Y = 90
Y = 135
X = 115-(90÷2)=70
2/3 of X = 70
X = 70x3/2= 105
Y = 135-(70÷2) = 100
4/5 of Y = 100
Y = 125
X = 105-(100÷4) = 80

AT first, there were 80 marbles in Box X and 125 marbles in Box Y.

Q4. (7+½)x2=15
(15÷2)+½ = 8
Number of chocolate bars that the third child got = 8.

Note
1st child got 32 chocolate bars
2nd child got 16 chocolate bars
3rd child got 8 chocolate bars
4th child got 7 chocolate bars

Total = 63 chocolate bars.

Q5. Women = 1/5
Men + Children = 4/5
Men = 2/5x4/5 = 8/25
Children = 1-1/5-8/25 = 12/25
12/25 of total = 266+266x2 = 798
8/25 of total = 532

Number of men in the hall = 532.

Q6. Cloths = 5/9
Gifts = 1/3
Mother + Left = 1-5/9-1/3 = 1/9
1/9 of the total = $1500+$560 = $2060
Total for Samuel= $2060x9 = $18540

Total for Samuel and Nigel = ($18540/4)x9 = $41715

Q7. 3N + J = 40.80
       2N + 2J = 45.20 (86 - 40.80)
        J - N = 4.4
 Rewriting N as J -4.4
       3J - 13.20 + J = 40.80, J = 54/3 = 13.50

Q8. 0.7 blue + 0.7 red --> 91 (adding both)
7 blue + 7 red --> 910 (times by 10)
1 blue + 1 red --> 130 (divide by 7)